2 ^ (10x ^ 2 - 8x - 23) + 2 ^ (5x ^ 2 - 4x - 12)

Вопрос пользователя:

2 ^ (10x ^ 2 - 8x - 23) + 2 ^ (5x ^ 2 - 4x - 12) - 3 = 0

Ответ нейросети:

This is a non-linear equation with exponents. To solve it, we can rewrite it as:

2^(10x^2 - 8x - 23) = 3 - 2^(5x^2 - 4x - 12)

Now, let's solve for x by setting the two expressions equal to each other:

2^(10x^2 - 8x - 23) = 3 - 2^(5x^2 - 4x - 12)

We can simplify this equation by letting y = 2^(5x^2 - 4x - 12):

2^(10x^2 - 8x - 23) = 3 - y

Now we have:

2^(10x^2 - 8x - 23) = 3 - y

2^(10x^2 - 8x - 23) = 3 - 2^(5x^2 - 4x - 12)

This equation can be solved numerically using a graphing calculator or software.

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